Leetcode 3021. Alice and Bob Playing Flower Game
Two-pile take-1-per-turn game reduces to parity: Alice wins iff x+y is odd (since exactly one flower is removed per move and Alice goes first), so the task is to count pairs (x,y) in [1..n]×[1..m] with opposite parity — computable from the counts of odd/even numbers in each range.
Question Timeline
See when this question was last asked and where, including any notes left by other candidates.
All Regions
Your account is free and you can post anonymously if you choose.